pcolormesh substitute in bokeh

surajmht238Apr 30, 2016 #1

Hello,
Just wanted to ask if anyone got this issue solved. I am trying to create something like the below example and would like to know how to do it in bokeh.
"
r = np.arange(0, 2*a ,0.01)
theta= np.linspace(0, 2 * np.pi ,100)

R, Theta = np.meshgrid(r, theta)
A,B = Rnp.cos(Theta),Rnp.sin(Theta)

def I(l,r,Theta):
Z=np.zeros(R.shape,np.float64)
Z[np.where(R<=a)] = jv(l, (x[m] * R[np.where(R<=a)]/ a)) * np.cos(l_Theta[np.where(R<=a)])
Z[np.where(R>a)] = jv(l,x[m]) / kv(l, t[m]) * kv(l,(t[m] * R[np.where(R>a)]/ a)) * np.cos(l_Theta[np.where(R>a)])
return Z

plt.pcolormesh(A, B, I(l,r,Theta))
plt.show()
"
this is the result:

Cheers

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BryanApr 30, 2016 #2

Hi,

You are trying to obtain a color-mapped image of 2D scalar array? Bokeh supports "image" and "image_rgba" glyphs, perhaps these can accomplish what you need:

http://bokeh.pydata.org/en/latest/docs/gallery/image.html

http://bokeh.pydata.org/en/latest/docs/gallery/image_rgba.html

pcolormesh is arguably a slightly higher level interface, perhaps a higher level color-mapped image chart would make sense for the bokeh.charts interface.

Thanks,

Bryan

···

On Apr 30, 2016, at 9:23 AM, surajmht238@gmail.com wrote:

Hello,
Just wanted to ask if anyone got this issue solved. I am trying to create something like the below example and would like to know how to do it in bokeh.
"
r = np.arange(0, 2*a ,0.01)
theta= np.linspace(0, 2 * np.pi ,100)

R, Theta = np.meshgrid(r, theta)
A,B = Rnp.cos(Theta),Rnp.sin(Theta)

def I(l,r,Theta):
Z=np.zeros(R.shape,np.float64)
Z[np.where(R<=a)] = jv(l, (x[m] * R[np.where(R<=a)]/ a)) * np.cos(lTheta[np.where(R<=a)])
Z[np.where(R>a)] = jv(l,x[m]) / kv(l, t[m]) * kv(l,(t[m] * R[np.where(R>a)]/ a)) * np.cos(lTheta[np.where(R>a)])
return Z

plt.pcolormesh(A, B, I(l,r,Theta))
plt.show()
"
this is the result:

Cheers

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