Assign names to each patch of patches

Community Support
1

As I understand it, you can add a name to a patch:

p.patch([1,2,3,4], [1,2,3,4], name=‘single_patch’)

and you can add a name to a patches object:

p.patches([[1,2,3,4], [1,2,3,4],], [[6,7,8,9], [6,7,8,9]], name=‘list_of_patches’)

However, is there a way to name each patch of a list of patches?

p.patches([[1,2,3,4], [1,2,3,4],], [[6,7,8,9], [6,7,8,9]], name=[‘first_patch’, ‘second_patch’])

The use case is that is makes selecting individual patches easier. So, in the case of a USA county map, I can name each patch according to its county name and then when I need to update some information for a given county then I can select for it directly.

2

Sean,

No, the name is actually attached to the glyph renderer, and the main purpose is to make finding the glyph renderer simple (e.g. with .select() or .select_one() functions) so that its properties can be modified.

For this use case I'd suggest making a mapping of the names you want to the indices in a python dict. If you need to use it in a CustomJS callback, then you can do something like:

    code = """

    var counties_index = %s;

    """ % my_mapping_dict

which to easily get the mapping into JS (just like Sarah used on the original non-app version of the Gapminder example).

Thanks,

Bryan

···

On Aug 26, 2016, at 10:36 AM, [email protected] wrote:

As I understand it, you can add a name to a patch:

p.patch([1,2,3,4], [1,2,3,4], name='single_patch')

and you can add a name to a patches object:

p.patches([[1,2,3,4], [1,2,3,4],], [[6,7,8,9], [6,7,8,9]], name='list_of_patches')

However, is there a way to name each patch of a list of patches?

p.patches([[1,2,3,4], [1,2,3,4],], [[6,7,8,9], [6,7,8,9]], name=['first_patch', 'second_patch'])

The use case is that is makes selecting individual patches easier. So, in the case of a USA county map, I can name each patch according to its county name and then when I need to update some information for a given county then I can select for it directly.

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3

Thanks, Bryan. I'll try that!