What does the "srouce=" parameter does?

For example in this simple example:

df = pd.DataFrame(from_some_dict)
tmp = ColumnDataSource(df)
p = figure()
p.scatter(df[‘datetime’], df[‘val’], source=tmp)
show§

``

I couldn’t figure out where to find the related documentation :frowning:

you would either do:

p.scatter(‘datetime’, ‘val’, source=tmp)

or

p.scatter(df[‘datetime’], df[‘val’])

the reason you would use source explicitly is to do something like this:

p = figure()

p.scatter(‘datetime’, ‘val1’, source=tmp)

p2 = figure()

p2.scatter(‘datetime’, ‘val2’, source=tmp)

show(VBox(children=[p, p2])

If you do this, then p1/p2 are connected (linked brushing)

···

On Fri, Feb 27, 2015 at 8:52 AM, Dror Atariah [email protected] wrote:

For example in this simple example:

df = pd.DataFrame(from_some_dict)
tmp = ColumnDataSource(df)
p = figure()
p.scatter(df[‘datetime’], df[‘val’], source=tmp)
show§

``

I couldn’t figure out where to find the related documentation :frowning:

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